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.4d^2-1d+.25=0
We add all the numbers together, and all the variables
.4d^2-1d+0.25=0
a = .4; b = -1; c = +0.25;
Δ = b2-4ac
Δ = -12-4·.4·0.25
Δ = 0.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{0.6}}{2*.4}=\frac{1-\sqrt{0.6}}{0.8} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{0.6}}{2*.4}=\frac{1+\sqrt{0.6}}{0.8} $
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